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Author Topic: OK, sum1 explain l337  (Read 1173 times)

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Offline Freddy Mercury

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Re: OK, sum1 explain l337
« Reply #25 on: September 01, 2007, 03:54:47 AM »
66666666666666@@@@@@@@@@@@@@@|-||-||-||-||-||-||-||-||-||-||-||-||-||-||-||-|!!!!!!!!!!!!!
*$+@|2+$ |2|_||\||\|1|\|6 1|\| (1|2(|3$*
\X/|-|@+ `/0|_| $@`/1|\|!

|=1><3[) |=0|2 6|23@+ j|_|$+1(3

Tekken 6 > All other fighterz x3

Offline Sync The Tempest

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Re: OK, sum1 explain l337
« Reply #26 on: September 01, 2007, 03:55:50 AM »
this is worse then algebra....

Offline Freddy Mercury

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Re: OK, sum1 explain l337
« Reply #27 on: September 01, 2007, 03:57:24 AM »
CAPSLOCK > L337speak

Tekken 6 > All other fighterz x3

Offline Sync The Tempest

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Re: OK, sum1 explain l337
« Reply #28 on: September 01, 2007, 03:58:24 AM »
ME NO SPEAK L337 NOOB
 thats it right so do i pass my quiz?
 XD||

Offline Freddy Mercury

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Re: OK, sum1 explain l337
« Reply #29 on: September 01, 2007, 04:05:38 AM »
ME NO SPEAK L337 NOOB
 thats it right so do i pass my quiz?
 XD||

Programming is MOAR crazy.

#include <stdio.h>

main ()
{   char cLetter;
     
     if (cLetter = 'A')
       printf("@");
     else if (cLetter = 'B')
       printf("8");
     else if (cLetter = 'C')
       printf("(");
     else if (cLetter = 'D')
       printf("[)");
     else if (cLetter = 'E')
       printf("3');

}

/* 8a51C pROGR4|\/| 1n c la|\|9U@GE O|\| 5|-|0\/\/i|\|9 +|-|e 1337 EKWIv4L3n+ OPh @ l4m35pE4|< L3T+3R  */

Tekken 6 > All other fighterz x3

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